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I need help solving this problem.-example-1

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Answer:

y =
(1)/(4) x -
(9)/(2)

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 4x + 38 is in this form with slope m = - 4

The line ST is perpendicular to line RS ( angles in a square are 90° )

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-4) =
(1)/(4)

y =
(1)/(4) x + c ← is the partial equation

To find c substitute (2, - 4) into the partial equation

- 4 =
(1)/(2) + c ⇒ c = - 4 -
(1)/(2) = -
(9)/(2)

y =
(1)/(4) x -
(9)/(2) ← equation of ST


User JackStat
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