Answer:
![\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/70we6dx7mg1inownawrlt0z29qav1gtr79.png)
Solution of the given system of equations
x = 3 and y= 2
Explanation:
Step(i):-
Given system of equations are
4x - y = 10 ...(i)
8x +5y = 34...(ii)
The matrix form
A X = B
![\left[\begin{array}{ccc}4&-1\\8&5\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}10\\34\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/jxg7yr42f8ymmxwjap36ula1lpj83wdc0e.png)
Step(ii):-
By using matrix inversion method

|A| = ad-b c = 4(5) - 8(-1) = 20+8 = 28
Given matrix
![A = \left[\begin{array}{ccc}4&-1\\8&5\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/nc5z1ko40ts1jzslxp3gqnqts6kd4xnt75.png)
![AdjA = \left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/6r5q85gkjv3wn5mkwwyhwure5oyg1jc44d.png)
![A djA = \left[\begin{array}{ccc}5&1\\-8&4\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/z61lahf0tw38qsjq6otcx3xwdz5nkotzjh.png)
Inverse of the matrix

![A^(-1) = (1)/(|A|) A djA =(1)/(28) \left[\begin{array}{ccc}5&1\\-8&4\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/2owljmyzl7ffm3wlojttdtsbrezzmaofx0.png)
Step(iii):-
The solution of the given system of equations by using matrix inversion method
X = A⁻¹ B
![X = A^(-1)B =(1)/(28) \left[\begin{array}{ccc}5&1\\-8&4\\\end{array}\right]\left[\begin{array}{ccc}10\\34\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/jny8isfperz58mcn21bs93mgrqoxb58ihj.png)
![X = A^(-1)B =(1)/(28) \left[\begin{array}{ccc}5X10+1X34\\-8X10+4X34\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/fnpazgodb0gogpu8kz8n7yz7bq975vokc1.png)
![\left[\begin{array}{ccc}x\\y\\\end{array}\right] =(1)/(28) \left[\begin{array}{ccc}84\\56\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/wntmcz2v08bmrdyvzrve1h67qekaqwfnun.png)
![\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/high-school/70we6dx7mg1inownawrlt0z29qav1gtr79.png)
Final answer:-
Solution of the given system x = 3 and y= 2