Answer:
10 miles.
Explanation:
Let x be the number of miles on Henry's longest race.
We have been given that Henry ran five races, each of which was a different positive integer number of miles.
We can set an equation for the average of races as:
![\frac{\text{The sum distances of 5 races}}{5}=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xdhvohkwhtunee0zfmlym28gzw3mtofctr.png)
As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.
Now let us substitute the distances of 5 races as:
![(1+2+3+4+x)/(5)=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gjwmk3wo80zyoh18wlrw6ndhhe6r0wl6ud.png)
![(10+x)/(5)=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2dly5sgrn79yn5reuuwo9ian9bntdcqd5s.png)
Let us multiply both sides of our equation by 5.
![(10+x)/(5)*5=4*5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o0qlr43poht0n5ku0ycaor9ovmkwgk50wk.png)
![10+x=20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6pwrgy9id00lqbylc7mrvyk3xwk14o74qt.png)
Let us subtract 10 from both sides of our equation.
![10-10+x=20-10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fqmajog0gk8zqknro4k8w8j5sr98ixitji.png)
![x=10](https://img.qammunity.org/2020/formulas/mathematics/college/2sq3213sbltyysvm7zbqw6n8nzorawzxqt.png)
Therefore, the maximum possible distance of Henry's longest race is 10 miles.