Answer:
Angles of the triangle are 90°, 50.77° and 39.23°.
Explanation:
Let the smallest side be x. Given that other sides are consecutive integers. So other sides are x+1 and x+2.
We have perimeter = 12 feet
So, x + x + 1 + x + 2 = 12
3x + 3 = 12
x = 3 feet
So the sides of the triangle are 3, 4 and 5 feet.
We have cosine formula
cosC

Consider a = 3 , b = 4 and c = 5
cosC

∠C = 90°
Similarly
cosB

∠B = 39.23°
∠A = 180-(90+39.23) = 50.77°
Angles of the triangle are 90°, 50.77° and 39.23°.