1 Answer

Kevin Cunnane · Answer 1 · 2020-10-27T11:06:31+0000

ANSWER

Step-by-step explanation

${h}^(2) = {y}^(2) + {4}^(2)$
This implies that,

${h}^(2) = {y}^(2) + 16...eqn1$

Also,

${h}^(2) + {x}^(2) = {16}^(2) ...eqn2$

And

${y}^(2) + {12}^(2) = {x}^(2)$

${y}^(2)={x}^(2) - 144 ...eqn3$

Put equation 1 into equation 2.

This will give us,

${y}^(2) + 16 + {x}^(2) = {16}^(2)$

${y}^(2) +{x}^(2) = {16}^(2) - 16$

${y}^(2) +{x}^(2) =16 ( 16 - 1)$

${y}^(2) +{x}^(2) =240...eqn4$

We put equation 3 into equation 4,

${x}^(2) - 144+{x}^(2) =240$

We simplify to get,

$2 {x}^(2) = 384$

${x}^(2) = 192$

x = √(192)

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions