Question

1. empirical formula for Cu2o4?

2. empirical formula for Zn3(NO3)4?

3. empirical formula for Ti2S2.5?

4. what is the molecular formula if the molar mass = 112.04 g/mol and the empirical mass of CO is 28.01 g/mol?

5. Empirical formula if you have 0.631m Cr & 1.90mol Cl?

Answer 1

We know that

1) empirical formula of a compound is the representation of a molecules with the elements in simplest mole ratio.

2) the molar mass is the actual proportion of moles of elements present in a molecule

3) there is a simple ratio between the molar mass and empirical mass a molecule

Now let us solve each problem

1) empirical formula of
`Cu_(2)O_(4)` will be
`CuO_(2)`

2) empirical formula of
`Zn_(3)(NO_(3))_(4)` will be
`Zn_(3)(NO_(3))_(4)`

3) empirical formula of
`Ti_(2)S_(2.5)` will be
`Ti_(4)S_(5)`

4) the molecular formula will be :

`Ratio=(molarmass)/(empiricalformula)=(112.04)/(28.01)=4`

the molecular formula = 4 X empirical formula = 4 X CO =
`C_(4)O_(4)`

5) the mole ratio of Cl and Cr is
`(1.90)/(0.631)=3`

empirical formula will be
`CrCl_(3)`