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Arithmetic of Functions problem
Open ended

Arithmetic of Functions problem Open ended-example-1

2 Answers

3 votes

Answer:

(g°h)(25) = 2

Explanation:

We have given two functions.

Firstly, we have to find two composition of two functions and secondly, we have to find (g°h)(25).

g(x) = x-3 and h(x) = √x

(g°h)(x) = g(h(x))

Putting given values in above formula,we have

(g°h)(x) = g(√x)

(g°h)(x) = √x-3

Putting x = 25 in above equation, we get

(g°h)(25) = √25-3

(g°h)(25) = 5-3

(g°h)(25) = 2

User Understack
by
8.0k points
5 votes

Answer: (gºh)(25)=2


Explanation:

1. This exercise is about Composition of functions, then you have:

2. Then, you have that

(gºh)(25)
=g(h(x))=√(x)-3

3. Now, you must substitute 25 into the function, as you can see below:

(gºh)(25)
=√(25)-3

4. Simplify the fucntion.

5. Therfore, you obtain:

(gºh)(25)
=5-3=2


User Iquellis
by
8.9k points

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