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In order for the parallelogram to be a rhombus, x=[?]. (9x+31) 32
HELP NEEDED ASAP

In order for the parallelogram to be a rhombus, x=[?]. (9x+31) 32 HELP NEEDED ASAP-example-1
User Biv
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1 Answer

4 votes
X = 3



Step-by-step explanation:

In a rhombus, the diagonals are perpendicular, creating four congruent right triangles.


Because the value of all three angles within any given triangle will add up to 180°, we can easily simplify the equation.

First, we’ll need to add our given angles. Which are 32° (as can be seen on the graph) and 90° (because any pair of perpendicular lines create four right angles and this triangle includes one of them).

32° + 90° = 122°


Next, we’ll subtract 122 from 180 to find the remaining angle measure

180 - 122 = 58

Then, we’ll subtract 31 with the subtraction property of equality

58 - 31 = 27

Right now, our equation looks like:

27 = 9x


In order to simplify this equation further, we must use the division property of equality to get x on its own.

27/9 = 9x/9

3 = x
User BraveNewCurrency
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