Question

URGENT !

for numbers 10 and 11 add and simplify.
there are rational expressions
PLEASE let me know how to solve it or explain .

Answer 1

`10. \: \frac{2 {x}^(2) - x }{3x + 3} + (2x - 1)/(3x - 3) \\ = \frac{(2 {x}^(2) - x)(3x - 3) + (2x - 1)(3x + 3) }{(3x - 3)(3x + 3)} \\ = \frac{6 {x}^(3) - 9 {x}^(2) + 3x + 6 {x}^(2) + 3x - 3 }{9 {x}^(2) - 9 } \\ = \frac{6 {x}^(3) - 3 {x}^(2) + 6x - 3 }{9 {x}^(2) - 9} \\ = \frac{2 {x}^(3) - {x}^(2) + 2x - 1}{3 {x}^(2) - 3 } \\ \\ 11. \: \frac{x + 4}{ {x}^(2) - 1} + (x + 4)/(x + 1) \\ = (x + 4 )/((x - 1)(x + 1)) + ((x - 1)(x + 4))/((x - 1)(x + 1)) \\ = \frac{x + 4 + {x}^(2) + 3x - 4}{ {x}^(2) - 1 } \\ = \frac{ {x}^(2) + 4x}{ {x}^(2) - 1}`

Answer 2

You first need to find a common denominator-see picture.