Question

PLEASE HELP

Solve each multiplication problem, use the cancellation method if possible, and reduce your answers.
a. 39⁄64 × 8⁄13
b. 2⁄3 × 1⁄5 × 4⁄7
c. 3⁄5 × 10⁄12 × 1⁄2
d. 4⁄9 × 54
e. 20 × 3 1⁄5
f. 11 × 2 7⁄11
g. 5 1⁄3 × 5 1⁄8
h. 10 2⁄3 × 1 3⁄8

Answer 1

QUESTION A

The given multiplication problem is

`(39)/(64) * (8)/(13)`

Factor each term to obtain;

`(13* 3)/(8*8) * (8)/(13)`

Cancel out the common factors to obtain;

`(1* 3)/(8*1) * (1)/(1)`

Simplify to get;

`(3)/(8)`

QUESTION B

The given multiplication problem is

`(2)/(3)* (1)/(5)* (4)/(7)`

This the same as

`(2* 1* 4)/(3* 5* 7)`

This simplifies to;

`(8)/(105)`

QUESTION C

The given problem is

`(3)/(5)* (10)/(12) * (1)/(2)`

This is the same as

`(3)/(5)* (5)/(6) * (1)/(2)`

`=(1)/(1)* (1)/(2) * (1)/(2)`

This simplifies to

`=(1)/(4)`

QUESTION D.

The given expression is

`(4)/(9)* 54`

Factor the 54 to obtain;

`(4)/(9)* 9* 6`

Cancel the common factors to get;

`(4)/(1)* 1* 6`

This simplifies to;

`=24`

QUESTION E

The given problem is

`20* 3(1)/(5)`

Convert the mixed numbers to improper fraction to obtain;

`=20* (16)/(5)`

`=4*5 * (16)/(5)`

Cancel the common factors to get;

`=4*1 * (16)/(1)`

`=64`

QUESTION F

The multiplication problem is

`11 * 2 (7)/(11)`

Convert the mixed numbers to improper fractions to obtain;

`11 * (29)/(11)`

Cancel out the common factors to get;

`=1 * (29)/(1)`

Simplify;

`=29`

QUESTION G

The given problem is

`5(1)/(3)* 5(1)/(8)`

Convert to improper fractions;

`=(16)/(3)* (41)/(8)`

Cancel out the common factors to get;

`=(2)/(3)* (41)/(1)`

`=(82)/(3)`

Convert back to mixed numbers

`=27(1)/(3)`

QUESTION H

The given expression is

`10(2)/(3) * 1(3)/(8)`

Convert to improper fraction to get;

`(32)/(3) * (11)/(8)`

Cancel common factors to get;

`=(4)/(3) * (11)/(1)`

Simplify

`=(44)/(3)`

Convert back to mixed numbers;

`=14(2)/(3)`