Question

How to find the permimeter of triangle ABC with the vertices of A(1,1) B(7,1) C(1,9)

Answer 1

Perimeter of the triangle=24 units

Explanation:

The given vertices of the triangle ABC are A(1,1), B(7,1) and C(1,9).In order to fin the perimeter, we need to find the lengths of the triangle.

Thus, AB=
`\sqrt{(7-1)^(2)+(1-1)^(2)}=√(36)=6`,

BC=
`\sqrt{(1-7)^(2)+(9-1)^(2)}=√(36+64)=√(100)=10` and

AC=
`\sqrt{(1-1)^(2)+(9-1)^(2)}=√(64)=8`

Now, Perimeter of the triangle= Sum of all the sides

=AB+BC+AC

=6+10+8

=24 units.

Thus, Perimeter of the triangle=24 units