Question

If an object is projected upward with an initial velocity of 129129 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 129 th=−16t2+129t. Find the height of the object after 44 seconds.

Answer 1

260 feet.

Explanation:

We have been given that an object is projected upward with an initial velocity of 129 ft per​ sec, its height h after t seconds is
`h(t)=-16t^2+129t`.

To find the height of object after 4 seconds, we will substitute t=4 in our given function.

`h(4)=-16*4^2+129*4`

`h(4)=-256+516`

`h(4)=260`

Therefore, the height of the object after 4 seconds will be 260 feet.