Answer:
We use log to solve only those equations in which we have our variables in power form.
Explanation:
Given : Margee thinks she can use logs to solve
, since logs seem to make exponents disappear but Margee is wrong
We have to explain the difference between equations like
and
We use log to solve only those equations in which we have our variables in power form.
Out of given equation only
has x in power form so we can apply log for solving the equation as,
![2=(1.04)^x\\\\\ \text{Taking ln both sides},\\\ln (2)=\ln (1.04)^x\\\\\\\\text{Using idenity} \ln a^b=b\ln a\\\\\\ln (2)=\ln (1.04)^x\\\\\text{on solving, we get}\\\\x=17.673](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8pyv9x55q038xq3w8a5ch3jzb9uepc8u8h.png)
While solving other equation ,
, we can directly take 8 root both side,
![56=x^8\\\\\\56^{(1)/(8)}=x^{(8*{(1)/(8)})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5pav6x0w29r9qtm7okewdqiqky6mfsda0o.png)
Thus, We use log to solve only those equations in which we have our variables in power form.