Question

I need help on this problem about proofs. I've gotten this far but I'm stuck. Please help me , I suck at math.

Answer 1

Explanation:

Givens

DTBC is a rhombus

<RTB = <FCB

Find

RD = DF

Solution

• <RTB = <FCB Given
• TD = DC Property of a Rhombus (all four sides are equal)
• <RDT = <FDC Vertically opposite angles are equal
• ΔRDT ≅ ΔFDC Δ = triangle. The Δs are congruent by ASA.
• RD = DF Parts of congruent triangles are congruent.

You will get problems like the way you were trying to do it. But you should just mark out what you know. I think that you might have forgotten about vertically opposite angles.