Question

Write an equation passing through the point (8,-2) and is perpendicular to -2x+y=-3

Answer 1

y = -1/2 x +2

Explanation:

We need to find the slope for the line -2x+y = -2

Add 2x to each side

-2x+2x +y = 2x -2

y = 2x-2

This is in the form y = mx+b

The slope is 2

We want a line perpendicular

That would be the negative reciprocal

m = -1/2

Now we have the slope of our new line and a point

m = -1/2 and (8,-2)

We can use point slope form

y-y1 = m(x-x1)

y --2 = -1/2 (x-8)

y+2 = -1/2 (x-8)

Distribute the -1/2

y+2 =-1/2x +4

Subtract 2 from each side

y+2-2 = -1/2x +4-2

y = -1/2 x +2