Question

A plane has a takeoff speed of 88.3 m/s and can accelerate at a rate of 3m/s to reach that speed. How long does the plane take to take-off.

Answer 1

v =
`(d)/(t)`

and

a =
`(v)/(t)`

We have acceleration and velocity so:

3 =
`(v)/(t)`

88.3 =
`(d)/(t)`

In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...

So...

`3t = v`

`88.3 = 3t`

Divide by three and

t = 29.4 s