Question

A ball is dropped from the top of a building. The distance in feet above the ground, represented by h(t), after t seconds can be modeled by the equation h(t)=-16t^2+180.

What is it's height after 3 seconds of falling?

Answer 1

324 feet

Explanation:

h(3) = 16(3)^2 + 180

h(3) = 16(9) + 180

h(3) = 144 + 180

h(3) = 324

Answer 2

The height of the ball after 3 seconds of falling is 36 feet above the ground.

How to find the height

To find the height of the ball after 3 seconds, you can substitute t = 3 into the equation h(t) = -16t² + 180

h(t) = -16t² + 180

h(3) = -16(3)² + 180

h(3) = -16(9) + 180

h(3) = -144 + 180

h(3) = 36