Question

What is the focus of the parabola with equation y = x2?

Answer 1

`focus=(0,(1)/(4))`

Explanation:

We are given equation of parabola as

`y=x^2`

we can also write as

`y=1(x-0)^2+0`

now, we can compare

`y=a(x-h)^2+k`

and find a , h , and k

a=1

h=0

k=0

now, we can use focus formula

`focus=(h,k+(1)/(4a))`

now, we can plug values

`focus=(0,0+(1)/(4* 1))`

`focus=(0,(1)/(4))`