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What is the focus of the parabola with equation y = x2?

User Evgeniy
by
8.1k points

1 Answer

1 vote

Answer:


focus=(0,(1)/(4))

Explanation:

We are given equation of parabola as


y=x^2

we can also write as


y=1(x-0)^2+0

now, we can compare


y=a(x-h)^2+k

and find a , h , and k

a=1

h=0

k=0

now, we can use focus formula


focus=(h,k+(1)/(4a))

now, we can plug values


focus=(0,0+(1)/(4* 1))


focus=(0,(1)/(4))


User Jeremy Warne
by
8.9k points

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