Answer:
![53(1)/(2)\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/anvx5703xhal8m0lf6a3x681amosuco68i.png)
Explanation:
we know that
The perimeter of a square is equal to
![P=4a](https://img.qammunity.org/2020/formulas/mathematics/high-school/toob55839gra82o37fku1w7y1rts1fzn6f.png)
where
a is the length side of the square
in this problem we have
![a=11(3)/(8)\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/lcuxm29q40xg1uq6d7unl7k7nqk54lf9r3.png)
convert to an improper fraction
![11(3)/(8)\ in=(11*8+3)/(8)=(91)/(8)\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/ieeq3m37gaqjakjf20d1p091claib45r94.png)
Find the perimeter of the square
![P=4(91)/(8)=45.5\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/ip8u3jadkxgwa9vg9bhp3ctjn9t2s2xgwl.png)
Remember to adds two extra inches for each corner
so
The wood needed is
![45.5\ in+2*4\ in= 53.5\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/rl6sanhdzh1qlto1qq8dwsm824twln78on.png)
convert to mixed number
![53.5\ in=53(1)/(2)\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/u8xhuwvl4ccl3av69jxlwhbdhr6kvhi0e1.png)