Question

an isosceles triangle has angle measures of 55, 55, and 70. the side across the 70 degree angle is 10 inches long. how long are the other sides?

Answer 1

8.72

Explanation:

Answer 2

The other sides of triangles are 8.72 in and 8.72 in

Explanation:

In a triangle ABC. Please find the attachment for figure.

`\angle A=70^(\circ)`

`\angle B=\angle C=55^(\circ)`

Side BC=a = 10 in

Using sine law of trigonometry,

`(a)/(\sin A)=(b)/(\sin B)=(c)/(\sin C)`

Substitute the given value into formula.

`(10)/(\sin 70)=(b)/(\sin 55)=(c)/(\sin 55)`

`(10)/(\sin 70)=(b)/(\sin 55)`

Cross multiply and we get

`b=\sin 55* (10)/(\sin 70)`

`b=8.72` in

It is a isosceles triangle. Therefore, b=c=8.72 in

Hence, The other sides of triangles are 8.72 in and 8.72 in