221k views
0 votes
Explain how you can approximate a cube root when the cube is not a perfect cube.

2 Answers

0 votes

Step-by-step answer:

You can use Newton's method as follows:

It is an iterative method, meaning that from an approximation (i.e. an approximate solution), we can refine the answer to get a closer approximation. By repeating the process (iteration), we can get an answer as accurate as we wish.

The basis of the formula is based on

x1=x0-f(x0)/f'(x0)

where

x0 is a given approximation

x1 is a better approximation

f(x) is a given function (for which we need the roots)

f'(x) is the derivative of the function.

Skipping all details and applying directly to find the cube root, we have

N=the number for which the cube root is desired

f(x)=x^3-N

f'(x)=3x^2

and x0 is an initial approximation that we need to provide (from the integer cubes, for example).

Say we need to find the cube-root of 124.

We know that 5^3 = 125, a rather close approximation, but the cube root is slightly less than 5.

To find a better approximation, we apply Newton's method, and calculate mentally:

x0=5, N=124

x1 = x0-(x0^3-124)/(3(x0^2)) [next substitute values]

= 5 - (125-124)/(3(5^2)) [ next simplify ]

= 5-1/75 [next, rearrange to calculate mentally ]

=5-(1/25)/3 [ next, substitute 1/25 = 0.04, 1/3 division can be done mentally ]

= 5 - 0.04/3 [ divide 0.04/3 mentally ]

= 5 - 0.013333 [ subtract ]

= 4.98667

(exact value = 4.98663, first approximation is already quite close)

User Austin Marusco
by
8.4k points
1 vote

Answer:

See below.

Explanation:

It would take a long time to explain . There is a good method called Newton's method which involves graphs of the type

y = x^3 - n and applying calculus to produce cycles of approximation until you'll get close to the required cubic root.

You'll find it on online videos.

User Stevec
by
7.3k points

No related questions found