Question

If 48 g of magnesium reacts with oxygen gas, how many grams of magnesium oxide will be formed according to the following equation? 2 Mg + O2 —-> 2 MgO

Answer 1

Using the balanced equation 2 Mg + O2 → 2 MgO, one can calculate the mass of magnesium oxide produced from 48 g of magnesium by using molar masses and stoichiometric conversions.

Step-by-step explanation:

The question if 48 grams of magnesium reacts with oxygen gas, how many grams of magnesium oxide will be formed, is a stoichiometry problem in chemistry. According to the balanced chemical equation 2 Mg + O2 → 2 MgO, two moles of magnesium react with one mole of oxygen to produce two moles of magnesium oxide. Magnesium and oxygen react in a 1:1 mole ratio to form magnesium oxide, so the mass of magnesium oxide formed from 48 g of magnesium can be calculated using molar masses and stoichiometric relationships.

To determine the mass of magnesium oxide produced, we use the molar mass of magnesium (24.305 g/mol) to find the moles of magnesium that 48 g corresponds to. This mole amount is then used in the stoichiometric conversion based on the balanced chemical equation to find the moles of magnesium oxide produced, which can then be converted back to grams using the molar mass of magnesium oxide (40.304 g/mol).

Answer 2

If 48 g of magnesium react with gaseous oxygen, 80 grams of magnesium oxide will form.

Step-by-step explanation:

First of all you must know the amount of mass that reacts and is produced from each compound stochemically (that is, the relationship between the amount of reagents and products in a chemical reaction).

For that you must know the atomic mass of each element, read in the periodic table:

• Mg: 24 g/mol
• O: 16 g/mol

Then, the compounds involved in the reaction have a molar mass, that is, the mass in one mole of the compound, of:

• Mg: 24 g/mol
• O₂: 2*16 g/mol= 32 g/mol
• MgO: 24 g/mol + 16 g/mol= 40 g/mol

But in the reaction 2 Mg + O₂ —-> 2 MgO it is observed that 2 moles of Mg and 1 mole of O₂ react, and 2 moles of MgO are formed. Then stoichiometrically they react and the following mass quantities are produced:

• Mg: 2 mol*24 g/mol= 48 g
• O₂: 1 mol*32 g/mol= 32 g
• MgO: 2 moles*40 g/mol= 80 g

By stoichiometry you can see that when reacting 48 g of Mg, 80 g of MgO are formed. Expressed in another way, if 48 g of magnesium react with gaseous oxygen, 80 grams of magnesium oxide will form.