Answer:
The correct answer is D.
Explanation:
Given:
General equation of second degree
x² + y² + 14 x + 2 y + 14 = 0
We must transform given equation to the canonical form from which we will read requested data.
The canonical form of the circle equation is:
(x - p)² + (y - q)² = r²
Where p and q are the coordinates of the center of the circle and r are radius. (p,q) = (x,y)
x² + 2 · x ·7 + 7² - 7² + y² + 2 · y · 1 + 1 - 1 + 14 = (x+7)² + (y+1) - 49 - 1 + 14 = 0
(x + 7)² + (y + 1)² = 36
We see that p = - 7 , q = - 1 and r = 6
God with you!!!