Question

if a firebird travels at a velocity of 0 to 60 mph in 4 seconds traveling east what was the acceleration of the firebird?

Answer 1

6.7 m/s^2

Step-by-step explanation:

The acceleration of the firebird is given by:

`a=(v-u)/(t)`

where

v is the final velocity

u is the initial velocity

t is the time taken

In this problem, we have:

`v=60 mph \cdot (1609 m/mile)/(3600 s/h)=26.8 m/s`

`u=0`

`t=4 s`

So, the acceleration is

`a=(26.8 m/s-0)/(4 s)=6.7 m/s^2`