Answer:
Volume(V) of the cone is given by:
![V = (1)/(3) \pi r^2h](https://img.qammunity.org/2020/formulas/mathematics/high-school/rfqafxxghaw667w0rcl7ivl4rv7y3yf08h.png)
where,
r is the radius of the cone and h is the height of the cone.
As per the statement:
A cone-shaped pile of gravel has a diameter of 30 m and a height of 9.1 m.
⇒diameter(d) = 30 m and h = 9.1 m
Diameter(d) is given by:
![d = 2r](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ciaq398ljhxe3kg7ar5thvid4tfaih1z0r.png)
then;
![30 = 2r](https://img.qammunity.org/2020/formulas/mathematics/high-school/llm2sftn7ihx7gyevk8evbjixcm204caua.png)
Divide both sides by 2 we have;
15 = r
or
r = 15 m
Substitute the given values and use
we have;
![V = (1)/(3) \cdot 3.14 \cdot 15^2 \cdot 9.1](https://img.qammunity.org/2020/formulas/mathematics/high-school/tih45toe7qm6ngwldph2jciq9evkufvogx.png)
![V = (1)/(3) \cdot 3.14 \cdot 225 \cdot 9.1](https://img.qammunity.org/2020/formulas/mathematics/high-school/sn04x0vghdqoju72ihs2q69aw5ftdh1tdy.png)
Simplify:
V = 2143.05 cubic meter.
Therefore, the best approximate the volume of the pile of gravel is,
![2143.1 m^3](https://img.qammunity.org/2020/formulas/mathematics/high-school/ghe6zelmkblb06kav736xd1sww15h9txfq.png)