Question

Nathaniel builds birds and birdhouses using Lego blocks. Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks. 43B + 215H? 3000 Nathaniel wants to build 50 birds using Lego blocks. How many birdhouses can he build at most with the remaining Lego blocks?

Answer 1

3 birdhouses

Explanation:

Answer 2

At-most 3 birdhouses.

Explanation:

Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.

We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality
`43B+215H\leq3000` represents the number of birds and birdhouses Nathaniel could build.

To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.

`43*50+215H\leq3000`

`2150+215H\leq3000`

Let us subtract 2150 from both sides of our inequality.

`2150-2150+215H\leq3000-2150`

`215H\leq850`

Let us divide both both sides of our inequality by 215.

`(215H)/(215)\leq(850)/(215)`

`H\leq3.953488`

As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.