Question

Can i have the x,y,z for this question? THanks!

Answer 1

x=4, y=-2, p=14

Explanation:

First simplify the LHS:

`LHS = (16p^8)^(3)/(2) * (216p^(-3))^{-(2)/(3)}`

`= 64 p^(12) * (1)/(36) p^(2)`

`=(16)/(9)p^(14)`

`=(2^4)/(3^2)p^14\\=2^43^(-2)p^(14)`

Hence x=4, y=2, p=14