Can i have the x,y,z for this question? THanks!

asked Jun 16, 2023 78.1k views

8 votes

by Sebix

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12 votes

Answer:

x=4, y=-2, p=14

Explanation:

First simplify the LHS:

$LHS = (16p^8)^(3)/(2) * (216p^(-3))^{-(2)/(3)}$

= 64 p^(12) * (1)/(36) p^(2)

=(16)/(9)p^(14)

$=(2^4)/(3^2)p^14\\=2^43^(-2)p^(14)$

Hence x=4, y=2, p=14

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