Question

A rod 14.0 cm long is uniformly charged and has a total charge of 222.0 mc. determine (a) the magnitude and (b) the direction of the electric field along the axis of the rod at a point 36.0 cm from its center

Answer 1

Electric field due to a charged rod along its axis is given by

`E = (kQ)/((L+r)(r))`

here we know that

L = 14 cm

r = distance from end of rod

r = 36 - 7 = 29 cm

Q = 222 mC

now we will have

`E = ((9 * 10^9)(222 * 10^(-3)))/((0.29)(0.43))`

`E = 1.6 * 10^(10) N/C`