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If x+y+z=0 Prove that (x^2+y^2+z^2)=4(xy+xz+yz)^2
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If x+y+z=0 Prove that (x^2+y^2+z^2)=4(xy+xz+yz)^2

User Riquelmy Melara
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1 Answer

2 votes
x + y + z = 0

(x + y + z)² = 0

x² + y² + z² + 2xy + 2xz + 2yz = 0

x² + y² + z² = -2(xy + xz + yz)

(x² + y² + z²)² = 4(xy + xz + yz)²
eh, not same
User Mty
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