Question

Y=-2x+6 3y-x+3=23 how do i solve this finding the x and the y

Answer 1

Explanation:

given system :

y=-2x+6 ........(1)

3y-x+3=23.........(2)

Substitute y = -2x+6 into (2) and solve for x :

3( -2x+6) - x +3 = 23

- 6x +18 - x +3 =23

- 7x = 2

x =- 2/7

Substitute : x into (1) : y = -2 (-2/7)+6 = 46/7

Answer 2

Answer 1

x= -(2/ 7)

Explanation:

Y=-2x+6 ---(equation 1)

3y-x+3=23 ------ (equation 2)

There are two unknowns in both the equation.

First substitute the value of y in equation 2:

3(-2x +6) - x +3 = 23

multiply the number outside the bracket with the number inside the bracket:

-6x + 18 - x + 3 = 23

Take all the x terms first:

-6x - x + 18 +3 = 23

-7x +21 = 23

-7x = 23-21

-7x = 2

x = -(2 / 7)

Answer 2

y= 46 / 7

Explanation:

Following the same steps to find the value of y

Y=-2x+6 ---(equation 1)

3y-x+3=23 ------ (equation 2)

There are two unknowns in both the equation.

First substitute the value of y in equation 2:

3(-2x +6) - x +3 = 23

multiply the number outside the bracket with the number inside the bracket:

-6x + 18 - x + 3 = 23

Now to find the value of y, put the value of x from answer 1 into equation to find y:

y= -2 × -(2 / 7) + 6

y= 4/7 +6

y= 46 / 7