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Please hurry .... Point Z is equidistant from the sides of RST which must be true?

Please hurry .... Point Z is equidistant from the sides of RST which must be true-example-1

2 Answers

3 votes

Answer:

The last answer is right

Explanation:

Because zs cuts the shape in half

User Linse
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8.4k points
4 votes

Answer with explanation:

In Δ R ST, Z C ⊥ RT, Z B ⊥TS, and Z A ⊥ RS.

Draw a circle Passing through points A,B and C.

→→Z A=Z B=Z C=Radius of the circle having center Z.

The Angle between Radius and tangent line measures 90°.

Also, The theorem which we will use here to find out which option is true among four options is:

⇒Length of tangent from external point to a circle are equal.

In Δ ZAS and Δ ZBS

∠ ZAS = ∠ ZBS→→→Each being 90°

ZA=ZB→→→Radii of circle

SA=SB→→Length of tangent from external point to a circle are equal.

Δ ZAS ≅ Δ ZBS→→→→→[SAS]

∠ ASZ ≅ ∠BSZ→→→→→→[CPCT]

Option D: ∠ ASZ ≅ ∠BSZ is correct among four options.

Please hurry .... Point Z is equidistant from the sides of RST which must be true-example-1
User Peter Svensson
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7.9k points