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Find the quotient. 12 a3 p4 ÷ -2a2p

User Zunilda
by
7.9k points

2 Answers

5 votes

Answer:

-6a / p³

Explanation:

Given expression is


12a^(3) p^(4) /(-2a^(2)p)

We have to simplify above expression.

We use two formulas in this expression.

xⁿ = 1/x⁻ⁿ (formula 1)


x^(m)×
x^(n) =
x^(m+n) ( formula 2)

using (formula 1) in given expression,we get


12 a^(3) p^(4) a^(-2) p^(-1) /-2

using (formula 2 ) in above expression ,we get


12a^(3-2) p^(4-1) /-2

12a¹p⁻³ / -2

2×6ap⁻³ / -2

-6a / p³ which is the answer.

User Yakiv Mospan
by
7.8k points
3 votes

Answer:
-6ap^3

Explanation:

Here the given expression is,


(12a^3p^4)/(-2a^2p)

=
(-12* a^3* a^(-2)* p^4* p^(-1))/(2)
( (1)/(a^x) = a^(-x) )

=
-6* a^(3-2)* p^(4-1)
( a^m* a^n = a^(m+n) )

=
-6 * a^1* p^3

=
-6ap^3

User Alcoholiday
by
7.4k points

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