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You took a second ball headed to a cliff. You dropped this ball straight down with a velocity of 9.3 m/s. The ball hit the ground exactly 8.0s after you released it. How high is the ciff?​
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You took a second ball headed to a cliff. You dropped this ball straight down with a velocity of 9.3 m/s. The ball hit the ground exactly 8.0s after you released it. How high is the ciff?​

User IngisKahn
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1 Answer

10 votes

Answer:

The cliff is 74.4m.

Step-by-step explanation:

The reading above clearly state that a ball is dropped straight down with the speed of 9.3m/s and hit the ground exactly at a time of 8.0s after you released it. And it is asking for the distance of the cliff.

In speed formula make distance the subject.

Therefore Distance = speed × time

Distance = 9.3mls × 8.0s = 74.4m

Therefore the cliff is 74.4m.

User Kirk Powell
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