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Given sintheta=6/11 and sectheta<0 find costheta and tan theta

2 Answers

7 votes

Answer: a

Step-by-step explanation: edge 2021

User Jaysingkar
by
5.4k points
6 votes

Answer:

cos∅=-
(√(85) )/(11)

tan∅ -
-(6√(85) )/(85)

Explanation:

sin∅ =
(6)/(11)

we know that

cos∅ =
√(1-sin^2∅ &nbsp;)

plugging the value of sin∅ gives


\sqrt{ 1-((6)/(11))^2\sqrt{ 1-((36)/(121))\\\sqrt{(85)/(121) } \\(√(85) )/(11\\)

therefore cos∅=-
(√(85) )/(11)

cos∅ is negative since sec∅ is negative

tan∅ =
(sin∅)/(cos∅)

=
\frac{(6)/(11) }{\frac{\-sqrt{85} &nbsp;}{11} } \\

on simplifying it ,we get

=-
(6)/(√(85) )

rationalizing it we get

-
-(6√(85) )/(85)

User Romanzo Criminale
by
5.4k points