Question

How many moles of ZnCl2 will be produced from 61.0g of Zn, assuming HCl is available in excess?

Answer 1

0.933 moles of ZnCl₂.

Step-by-step explanation

How many moles of Zn in 61.0 grams of zinc?

The relative atomic mass of zinc Zn is 65.38. As a result, the mass of one mole of Zn atoms is 65.38 grams.

`n = (m)/(M) = \frac{61.0\; \text{g}}{65.38 \; \text{g} \cdot \text{mol}^(-1)} = 0.933 \; \text{mol}`

There are 61.0 / 65.38 = 0.933 moles of Zn atoms in 61.0 grams of Zn.

How many moles of ZnCl₂ can be produced from 0.933 moles of Zn?

Zn reacts with HCl by the equation:

Zn + 2 HCl → ZnCl₂. Balanced.

Each mole of Zn atoms combine with two moles of HCl to produce one mole formula unit of ZnCl₂. 0.933 moles of Zn atoms reacts with excess HCl to produce 0.933 moles formula units of ZnCl₂.