Answer:
Width: 7
Length: 14
Explanation:
The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let
represent the width.
Since the length is 7 feet longer, we can represent the length by
.
Now that we have our values for the length and the width we can multiply them together to find our area.
![(x)(x+7)=x^(2) +7x](https://img.qammunity.org/2020/formulas/mathematics/high-school/er2840bb4juwmxfif6ouilwta9giw7jipd.png)
Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.
![(x+7)(x+14)](https://img.qammunity.org/2020/formulas/mathematics/high-school/wofrpcfuikfhv3lo1mgcr7c7q0qqx3mn5d.png)
And multiply our area by 3.
![3(x^(2) +7x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mz3cwb4ocdsr9yuseb1yy087l3r3w3myii.png)
set these equal to each other to find your new equation.
![(x+7)(x+14)=3(x^(2) +7x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/s8ajoekfmmyv7dvzzqi5qj6l72khz0q3qq.png)
Now you need to solve for
. To do this first muliply
and
.
![(x+7)(x+14)=\\x^(2) +14x+7x+98=\\x^(2) +21x+98](https://img.qammunity.org/2020/formulas/mathematics/high-school/si9dmjiprezo1ajef82ltsgmmesc9rywus.png)
Then multiply
![3(x^(2) +7x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mz3cwb4ocdsr9yuseb1yy087l3r3w3myii.png)
![3(x^(2) +7x)=\\3x^(2) +21x](https://img.qammunity.org/2020/formulas/mathematics/high-school/8qmfof1x8cibd5cr9u5fca9hqbrq9fk7r2.png)
Now you can begin solving for
.
![x^(2) +21x+98=3x^(2) +21x](https://img.qammunity.org/2020/formulas/mathematics/high-school/byhk6142wuypefg72motdfj10yoa3azsu3.png)
Subtract
from both sides.
![21x+98=2x^(2) +21x](https://img.qammunity.org/2020/formulas/mathematics/high-school/e9wmmewhpemokv8jdsz647bu86iygm3fuy.png)
Subtract
from both sides.
![98=2x^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/e1fequzx2n463f3t77rfbi73tax258kxen.png)
Divide by 2.
![49=x^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/63s0s8unlo9az223m8negyxugji8x7b832.png)
And finally take the sqaure root of both sides.
![\sqrt{x^(2) }=√(49)\\x=7](https://img.qammunity.org/2020/formulas/mathematics/high-school/d309vwvd6jxy79lyuhorus0r1zb8mz63q6.png)
Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 and -7, in this case we only get +7.
Now that we have the value of
, we can plug it into our original values.
For width we simply get 7.
For length we get 7+7=14
To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.