Answer:
Explanation:
Let the graph is of a function denoted as y = .03(x²)(x²-25)
Then we can solve the function as y = .03(x²)(x-5)(x+5) ---(As we know (a²-b²) = (a-b)(a+b))
Now we can find the value of y by putting the value of x in the given equation.
Here this function is defined at x = 0,-5 and 5.
For the value of x = 0 y = 0
for x = -5 y = 0 and for x = 5 y = 0
Here the points (0,0) (-5,0) & (5,0) lie on the graph which is true for first graph.Therefore graph number one is the graph for .03(x²)(x²-25)