Answer:
1. A 2-kg bowling ball sits on top of a building that is 40 meters tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:
KE = 0 (because velocity is 0)
PE = mgh = 2kg*9.8m/s^2*40m= 784 joule
2. A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:
Both
KE = [1/2]m*v^2 = [1/2](2kg)(5m/s)^2 = 25 joul
PE = mgh = 40 joule
3. A 2-kg bowling ball rolls at a speed of 10 m/s on the ground. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:
KE = [1/2]m(v^2) = [1/2]2kg*(10m/s)^2 = 100 joule
GPE = mgh = 0
1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?
KE = [1/2]m(v^2) => v = √[2KE/m] = √[2*50,000joules/1000kg] = 10m/s
2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?
GPE = mgh => h = GPE / (mg) = 39,200 joules / (200kg * 9.8m/s^2) = 20m
3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?
KE = [1/2]m(v^2) => v = √ [ 2KE/m] = √[2*12.5 j / 1kg] = 7.9 m/s
GPE = mgh => h = GPE/(mg) = 98/(1kg*9.8m/s^2) = 10 m
Explanation:
bc someone else said it