Question

When x 4 - 2x 3 - 3x 2 - 4x - 8 is divided by x - 2

Answer 1

`(x^4-2x^3-3x^2-4x-8)/(x-2)=(x^3-3x-8)-(28)/(x-2)`

Explanation:

We are given

Dividend is

`=x^4-2x^3-3x^2-4x-8`

Divisor is

`=x-2`

now, we can use long division

so, we get

Quotient as

`Q(x)=x^3-3x-10`

Remainder is

`R=-28`

we can write as

`(x^4-2x^3-3x^2-4x-8)/(x-2)=(x^3-3x-8)-(28)/(x-2)`