Question

Consider the quadratic function f(x) = x2 – 5x + 6.

What are the values of the coefficients and constant in the function?

a =

b =

c =

Answer 1

The answers would be:

a = 1

b = -5

c = 6

Explanation:

We can tell this because a is always equal to the coefficient of x^2. Since there is no number there, it is assumed to be 1.

b is always the coefficient of x, which in this case is -5.

c is the constant listed at the end of the equation.

Answer 2

For this case, we have a quadratic function of the form:

`ax ^ 2 + bx + c`

If we want to find the roots of the equation
`ax ^ 2 + bx + c = 0`, we have:

`x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}`

If we have,
`x ^ 2-5x + 6` then we have two coefficients given by:

`a = 1\\b = -5`

And the constant term:

`c = 6`

Answer:

`a = 1\\b = -5\\c = 6`