Question

Z varies directly as x^3 and inversely as y^3. if z=59 when x=8 and y=8, find Z if x=3 and y=4

Answer 1

`z=(kx^3)/(y^3)\\\\\\59=(k\cdot 8^3)/(8^3)\\k=59\\\\\\z=(59x^3)/(y^3)\\\\\\z=(59\cdot 3^3)/(4^3)=(1593)/(64)`