Question

Terry owns a triangular piece of land that has three corner fence poles at A, B,and C. The three poles are plotted on a grid in units of feet at A(1000, 8000), B(6000, 7000), and C(5000, 1000). Terry wants to fence his land. To the nearest foot, how much fence does he need?

Answer 1

Answer: 19,244 ft

Explanation:

1. To solve this exercise you can apply the formula for calculate the distance between two points, which is:

`d=\sqrt{(x_2-x_1)^(2)+(y_2-y_1)^(2)}`

2. Then:

`d_(AB)=\sqrt{(6,000-1000)^(2)+(7,000-8,000)^(2)}=5,099.01`

`d_(AC)=\sqrt{(5,000-1000)^(2)+(1,000-8,000)^(2)}=8,062.25`

`d_(AC)=\sqrt{(5,000-6000)^(2)+(1,000-7,000)^(2)}=6,082.76ft`

3. Add the distance obtained to calculate the perimeter of the triangle. Therefore, the fence needed to the nearest food is:

`P=5,099.01ft+8,062.25ft+6,082.76ft=19,244.02ft=19,244ft`