23.3k views
3 votes
What is the perimeter of a rectangle that has a width of 2×√75 + 4×√48 and a length of 1/2×√100

User Palotasb
by
8.0k points

1 Answer

4 votes

Answer:

10 + 52
√(3)

Explanation:

Perimeter = 2l + 2w ( l is length and w is width )

l =
(1)/(2) ×
√(100) =
(1)/(2) × 10 = 5

b = 2
√(75) + 4
√(48)

= 2
√(25(3)) + 4
√(16(3))

= 2 × 5
√(3) + 4 × 4
√(3)

= 10
√(3) + 16
√(3) = 26
√(3)

--------------------------------------------------------------------------

Perimeter = (2 × 5) + (2 × 26
√(3)) = 10 + 52
√(3)



User Cthiebaud
by
8.3k points

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