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How many solutions does the system have?

y=−2x+1
y=−2x^2+1

User Retros
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1 Answer

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Answer:

hello two solutions

Explanation:

y=−2x+1

y=−2x²+1

-2x² + 1 = -2x + 1

2x² = 2x ... ( add -1 and multiply by -1)

2x² - 2x =0

2x(x - 1) = 0

2x = 0 or x - 1 = 0

x = 0 or x = 1 two solutions

User Jason Van Anden
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