Question

Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.650 µC charge and flies due west at a speed of 540 m/s over the Earth's south magnetic pole, where the 8.00 ✕ 10−5 T magnetic field points straight up. What are the magnitude (in N) and direction of the magnetic force on the plane?

Answer 1

Answer :
`F=2808* 10^(-11)\ N`

Explanation :

It is given that,

Charge,
`q=0.650\ \mu C=0.65* 10^(-6)\ C`

Velocity of Aircraft,
`v=540\ m/s` (in west)

Magnetic field,
`B=8 * 10^(-5)\ T` ( in north )

Using the relation as :

`F=q(v* B)`

Magnetic force is ,

`F=0.65* 10^(-6)\ C* 540\ m/s* 8 * 10^(-5)\ T`

`F=2808* 10^(-11)\ N`

Using Right hand thumb rule, the direction of force is in the plane perpendicular to the velocity and the magnetic field i.e.
`-\hat{k}`.