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Order each group of numbers from least to greatest. Square root of 8, 2, square root 7/2

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Answer:


\sqrt{(7)/(2)}, 2, √(8)

Explanation:

Find the value if each number:


  • √(8) is between
    √(4)=2 and
    √(9)=3. This means the value is between 2 and 3.
  • 2 is 2

  • \sqrt{(7)/(2)}=√(3.5) is between
    √(1)=1 and
    √(4)=2. So its value is between 1 and 2.

From least to greatest, the values order as
\sqrt{(7)/(2)}, 2, √(8)

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