Answer:
The correct option is B.
Explanation:
According to the Pythagoras theorem, in a right angled triangle the sum of squares of both legs is equal to the square of hypotenuse.
![hypotenuse^2=perpendicular^2+base^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eiqdhoo100s2qkip9t5w3xaayigyjgsjp7.png)
From the given triangle it is clear that the measure of both legs are 6 units and √(63) units , and the measure of hypotenuse is 10 units.
![(10)^2=(√(63))^2+(6)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1x43nss3grsnwq0r54daz83cfzf3s5c75e.png)
Solve the LHS,
![LHS=(10)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/haha4e24pn2i8u29ohmlrffcqyxkkgd7em.png)
![LHS=100](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5p027o0jsuah7z36ftrvnn0d3n3iemonj2.png)
Solve the RHS,
![RHS=(√(63))^2+(6)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6u7iq0jx4ty1nbj2ou41bcidrl160dj4kv.png)
![RHS=63+36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3a1j36fl3ymh34vqcztw41zg98672e2bp3.png)
![RHS=99](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j5n6k8chbf3ql2tqbw16bm98evq9xffhei.png)
![LHS\\eq RHS](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ywzqvc4flcvdiwt4ykp7hm8mfphpgp689k.png)
The given triangle FGH is not a right angled triangle, therefore the correct option is B.