Question

Solve x^2-1=0 using quadratic formula

Answer 1

I am thinking that my solution is correct

Answer 2

1 or -1

Explanation:

To start, let's add in the 0x. We get
`x^2 + 0x - 1 = 0`. Now, we use the quadratic formula which is
`(-b\pm√(b^2-4ac))/(2a)`, where a, b, and c are the coefficients in a quadratic ax^2 + bx + c, so plugging in the values, we get
`(-0\pm√(0^2-4(1)(-1)))/(2) \implies (0\pm√(0-(-4)))/(2) \implies (0\pm√(4))/(2) = (0\pm2)/(2) \implies 1$ $ or $ $ -1. \blacksquare`