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What is the cube root of 27what is the factorization of 216x^12 - 64

2 Answers

3 votes

Answer:

true

Explanation:

User Alexandre Huat
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4 votes

Answers:

1) 27 is the same as multiplying three times three times three:


(3)(3)(3)={3}^(3)=27 (1)

Now, the cube root of 27 can be written as:


\sqrt[3]{27}={(27)}^{(1)/(3)} (2)

Knowing the information given by (1) we can rewrite (2) as:


{({3}^(3))}^{(1)/(3)}

Applying the rule of exponents with the same base, which in this case is 3:


{(3)}^{3((1)/(3))}=3

Finally:


\sqrt[3]{27}=3

2) We have the following expression:


216{x}^(12)-64

That can be factored by taking the common factor, which in this case is 8:


8(27{x}^(12)-8)

Then:


216{x}^(12)-64=8(27{x}^(12)-8)

User Cancerian
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