Question

A sled of mass 10 kg slides along the ice. it has an initial speed of 2 m/s but stops because of friction. How much work is done by friction?

A. 0 J
B. -20 J
C. -10 J
D. 20 J

Answer 1

Answer:-20

Step-by-step explanation:

Answer 2

Answer: The correct answer is option B.

Step-by-step explanation:

Mass of the sled = 10 kg

Initial speed of the sled = 2 m/s

Kinetic energy of the sled =
`(1)/(2)mv^2`

`(1)/(2)* 10 kg* (2 m/s)^2=20 Joules`

Work done by the sled = 20 joules

The work done by the friction will be in opposite direction and equal to the magnitude of the work done of the sled that - 20 J.

Hence, correct answer is option B.